Question
In a Leichtman Research Group survey of 1050 TV households, 75% of them had at least one Internet-connected TV device (for example, Smart TV, standalone
In a Leichtman Research Group survey of 1050 TV households, 75% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 79%. Test that claim using a 0.10 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution.
Let p denote the population proportion of all homes with at least one Internet-connected TV device. Identify the null and alternative hypotheses.
H0: p = 0
H1: p 0
(Type integers or decimals. Do not round.)
Part 2
Identify the test statistic.
z=?
(Round to two decimal places as needed.)
Part 3
Identify the P-value.
P-value=?
(Round to three decimal places as needed.)
Part 4
State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim.
- Accept/Reject/Fail to reject the null hypothesis. There is/is not sufficient evidence to support/warrant rejection of the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 79%
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