In a Leichtman Research Group survey of 1050 TV households, 74.9% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 78%. Test that claim using a 0.01 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. . . . Let p denote the population proportion of all homes with at least one Internet-connected TV device. Identify the null and alternative hypotheses. Ho: P H : P (Type integers or decimals. Do not round.) Identify the test statistic. z= (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There sufficient evidence to the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 78%.A data set lists weights (lb) of plastic discarded by households. The highest weight is 5.19 lb, the mean of all of the weights is x = 2.201 lb, and the standard deviation of the weights is s = 1.088 lb. a. What is the difference between the weight of 5.19 lb and the mean of the weights? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the weight of 5.19 lb to a z score. d. If we consider weights that convert to z scores between - 2 and 2 to be neither significantly low nor significantly high, is the weight of 5.19 lb significant? a. The difference is |lb. (Type an integer or a decimal. Do not round.) b. The difference is standard deviations. (Round to two decimal places as needed.) c. The z score is z = (Round to two decimal places as needed.) d. The highest weight isFind the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. 108 124 The area of the shaded region is . (Round to four decimal places as needed.)