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In a Leichtman Research Group survey of 1100 TV households, 75.2% of them had at least one Internet-connected TV device (for example, Smart TV, standalone

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In a Leichtman Research Group survey of 1100 TV households, 75.2% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 83%. Test that claim using a 0.10 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Let p denote the population proportion of all homes with at least one internet-connected I V device. Identity the null and alternative hypotheses. Ho: P H1 : P (Type integers or decimals. Do not round.) Identify the test statistic. z= (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There V sufficient evidence to the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 83%.In a Leichtman Research Group survey of 1100 TV households, 75.2% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 83%. Test that claim using a 0.10 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Let p denote the population proportion of all homes with at least one internet-connected I V device. Identity the null and alternative hypotheses. Ho: P H1 : P (Type integers or decimals. Do not round.) Identify the test statistic. laces as needed.) Reject Accept places as needed.) Fail to reject but the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There sufficient evidence to the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 83%.In a Leichtman Research Group survey of 1100 TV households, 75.2% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 83%. Test that claim using a 0.10 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Let p denote the population proportion of all homes with at least one internet-connected | V device. Identity the null and alternative hypotheses. Ho: P H1 : P (Type integers or decimals. Do not round.) Identify the test statistic. z= (Round to two decimal places as needed.) Identify the P-value. P-value = is (Round to three decimal places as needed is not State the conclusion about the null hypoth e final conclusion that addresses the original claim. the null hypothesis. There sufficient evidence to the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 83%.In a Leichtman Research Group survey of 1100 TV households, 75.2% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 83%. Test that claim using a 0.10 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Let p denote the population proportion of all homes with at least one internet-connected I V device. Identity the null and alternative hypotheses. Ho: P H1 : P (Type integers or decimals. Do not round.) Identify the test statistic. z= (Round to two decimal places as needed.) Identify the P-value. P-value = support (Round to three decimal places as needed.) warrant rejection of State the conclusion about the null hypothesis, as well as the final concl al claim. the null hypothesis. There sufficient evidence to the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 83%

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