In a one-dimensional collision, the energy loss that can occur ranges from none at all to a maximum when two objects stick together. When the two objects do not stick together, there is still a range of possible energy loss, but it is somewhat restricted. In this application, you will determine the range of energy losses for a 20 collision. This problem will investigate what happens when a rock of mass 400 g is thrown from a distance at block of mass 4.25 kg that is placed precariously on a pole. The rock proceeds to hit the block at a speed of 1.9 m/s moving in a direction diagonally downward. In particular, you will find the range angles that the block can fall after the collision. art 2 of 3 Now, assume the rock hits the side of the block from the left, so that the direction of action is perpendicular to the block's vertical face - in the y-direction. However, the two objects do not stick together. The angle of approach is 450 from the vertical. In this step, you will investigate the case where the most energy is lost in the collision U u (a) First, write the initial velocity of the rock in physical form. V = 1.9 mis (1.3435 X y + 1.3435 x 2) (b) Now, write it in mathematical form. V = ly + Now, you're ready to set up the momentum equation. Use the information above to find the initial momentum, and set up the momentum equations to find the final velocity. (c) Set up the momentum table. Direction Initial Final Uy (d) Find the final velocity of the block. U = y + 0 mis 2 (e) Find the final velocity of the rock. Vb = ly + 2 (f) Rewrite that in physical form. Vb = ly + 2 )