Question
In a plant, mushrooms are produced as a substitute for meat products from food waste. The reaction takes place in a so-called air-lift reactor whose
In a plant, mushrooms are produced as a substitute for meat products from food waste. The reaction takes place in a so-called air-lift reactor whose inflow consists of 3% ethanol, 15% waste and the rest water (mass-%).
Before the reactor, the inflow is sterilized at 100 oC, which is done by first raising the temperature from 20 oC to 100 oC in a heat exchanger 1, see Fig 1. Then follows a holding tank where the sterilization itself happens. After the sterilization, the stream is cooled to the reaction temperature of 30 oC with a cooling water stream which maintains the temperature Tcooling (In) and which is heated to the temperature Tcooling(out). The heating medium in heat exchanger 1 is saturated water vapor 5 bar.
The company wants to improve energy efficiency and improve the economics of the process. One of the proposals is shown in Fig 2. The proposal is to preheat material stream 1 before heat exchanger 1 with the hot stream off the sterilization. In addition to reducing heating costs, cooling water consumption is also reduced. The change means that a new heat exchanger (NH) must be purchased and new pipe systems, valves, etc. must be installed. The old heat exchanger 2 is discarded. The company's requirements for payback time of this type of investment are given in the table below.
The question is to assess using the pay-off method whether the process change is a profitable investment.
Data
Heat exchanger purchase price (USD) = 1.66C, where log (C) = K1 + K2 log(A) + K3 (log A)2
A = heat exchanger area (m2) K1 = 4.1884 K2 = -0.2503 K3 = 0.1974
The total cost of the investment (= basic investment) is obtained by multiplying the heat exchanger's purchase price with factor 4.
Dollar exchange rate: SEK 9 Cp (ethanol) = 2.4 kJ/kg K Cp (water) = 4.2 kJ/kg K Cp (biomass) = 2.2 kJ/kg 0C Steam cost: SEK 300/MWh Cost of cooling water: SEK 5/m3
The heat exchanger's U-value and cooling water temperatures are given by the following table.
Stream 1 (kg/s) | U (W/m2 oC) | Tcooling(in) (oC) | Tcooling(out) (oC) | Payback period (years) |
4 | 1100 | 10 | 37 | 5 |
Fig 1. Current process
Flow | Temp |
1 | 20 |
2 | 100 |
3 | 100 |
4 | 30 |
Steam | Saturated water vapor 5 bar |
Condensate | Saturated water, 5 bar |
Fig 2. Improved process
Flow | Temp | |
1 | 20 | |
2 | 100 | |
3 | 100 | |
4 | 30 | |
5 | - | |
Steam | Saturated water vapor 5 bar | |
Condensate | Saturated water, 5 bar | |
Note: T = 90 C temperature of flow 5
added heat steom 5 bor cooled heot condensate, 5bor to reactorStep by Step Solution
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