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In a problem set, the answer key stated that for K + [PdCl 3 (NH 3 )] , the Pd-containing ion has a C 2v

In a problem set, the answer key stated that for K+[PdCl3(NH3)], the Pd-containing ion has a C2v point group and is square planar. How is this possible with three of one ligand and one of another?

Similarly for [Pd(NH3)3Cl]+Cl. Is the answer key wrong?

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