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In a random sample of 40 refrigerators, the mean repair cost was $ 144.00 and the population standard deviation is $ 18.50 . A 90

In a random sample of 40 refrigerators, the mean repair cost was $144.00 and the population standard deviation is $18.50.

A 90% confidence interval for the population mean repair cost is (139.19,148.81).

Change the sample size to n=80. Construct a 90% confidence interval for the population mean repair cost. Which confidence interval is wider? Explain.

Construct a 90% confidence interval for the population mean repair cost.

The 90% confidence interval is ( __ ,__ ).

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