In a random sample of 40 refrigerators, the mean repair cost was $112.00 and the population standard deviation is $15.30. Construct a 90%

confidence interval for the population mean repair cost. Interpret the results.Construct a 90% confidence interval for the population mean repair cost.

A. With 90% confidence, it can be said that the confidence interval contains the true mean repair cost.

B. With 90% confidence, it can be said that the confidence interval contains the sample mean repair cost.

C. The confidence interval contains 90% of the mean repair costs.