In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results. The 95% confidence interval for the population mean u is ( 47.41, 72.59 ). (Round to two decimal places as needed.) The margin of error is $. (Round to two decimal places as needed.)