In a recent survey of 1000 US adults conducted in January 2013, 57% said they dine out at least once per week. The standard error for this estimate is 0.016. Use the normal distribution to find a 95% confidence interval for the proportion of US adults who dine out at least once per week. Round to two decimal places. Interpret your answer. Include all your steps or write an explanation of how you determined your interval.

Formula used:_____ Margin of error:___________________

Interval: _____________________ Interpretation:__________________________________________________

Explanation:___________________________________________________________________________________