In a saloon, a cowboy slides an empty beer mug down the counter for a refill while the barkeep has his back turned while filling a glass. The height of the counter is H = 1.06 m. The mug slides off the counter and hits the floor D = 1.5 m from the base of the counter. (a) How long after the mug leaves the counter does it take the mug to hit the ground? t = .3379 sec x (b) With what speed did the mug leave the counter? Vo = 3.27 m/s (c) Take the point on the floor just below the end of the counter to be the origin. What are the initial conditions for this problem? *(0) = 0m V y + 1.06 m #(0) = 3.27 m/s y + 0 m/s (d) Write the trajectory function of the mug. *(t) = [ x + t + t 2 ) y + It + t2) 2 (e) What is the final velocity of the mug? (t,) = 4.49 m/s 2 (f) Rewrite this in physical form (magnitude times direction). V(t) = ly + 2 )