In a sample of 150 college students, the proportion who report studying more than 6 hours per week is 0.22. Use this information to find the 95% and 99% confidence intervals for p. (a) 95% Confidence Interval p-hat = This is given in the scenario SE of p-hat = This is (p(1-p) n Critical Value (z-star) = This is from the table in your notes Margin of Error = This is SE of p-hat times critical value Confidence Interval: up to Subtract MOE from p-hat, then add MOE to p-hat (b) 99% Confidence Interval p-hat = SE of p-hat = This is p(1-p) Critical Value (z-star) = Margin of Error = This is SE of p-hat times critical value Confidence Interval: up to Subtract MOE from p-hat, then add MOE to p-hat