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In a sample of n=100 adolescents, the mean was calculated to be M=45.88. The normal population has a mean of = 40 and a standard

In a sample of n=100 adolescents, the mean was calculated to be M=45.88. The normal population has a mean of = 40 and a standard deviation of =15. Does the sample provide evidence to conclude that the sample is significantly different from those of the general population? Use a two-tail test with = 0.01.

1a) What is the null and alternative hypothesis?

1b) What is the positive value ofzcrit (the cut off for the critical region)?

1c)What is M?

1d)What is the z-score of the sample (also sometimes called the zobt)? Round your answers to 2 decimal places if needed.

1e)What conclusion do you draw?

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