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In a single loop or series Circuit, Kirchoffs' second law states that the sum of the voltage drops across an inductor, resistor, and Capacitor
In a single loop or series Circuit, Kirchoffs' second law states that the sum of the voltage drops across an inductor, resistor, and Capacitor is equal to the impressed Voltage E(t). Now it is known that the voltage drop across the inductor = L dt, at the voltage drop across the resistor Ri(t), t and the voltage drop. the capacitor = + ficpude, where i(t) is the current and L,R, and C are constants. It follows that the current in a circuit, such that shown in the figure, is the integro-differental 00000 governed by equation (E) t di + Ri+! Sicpads = Ele L di across 1 = C R problem a Sir Determine the current i(t) in Single loop L.R.C Circuit when L = 0.1 henry, R=20 Ohms, C=10 farad, i(0) = 0, and the impressed voltage Elt) is as given in the following figure 1204El) 120t
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