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In a survey, people were asked whether they thought sun went around the planet Earth or vice versa. Of 1877 people, 338 thought the sun

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In a survey, people were asked whether they thought sun went around the planet Earth or vice versa. Of 1877 people, 338 thought the sun went around Earth. a. What proportion of people in the survey believed the sun went around Earth? b. Find a 95% confidence interval for the proportion of all people with this belief. c. Suppose a scientist said that 25% of people in the general population believe the sun goes around Earth. Using the confidence interval, would you say that was plausible? Explain your answer In a 2008 survey, people were asked their opinions on astrology - whether it was very scientific, somewhat scientific, or not at all scientific. Of 1431 who responded, 73 said astrology was very scientific. a. Find the proportion of people in the survey who believe astrology is very scientific. b. Find a 95% confidence interval for the population proportion with this belief. . Suppose a TV news anchor said that 5% of people in the general population think astrology is very scientific. Would you say that is plausible? Explain your answer. A poll asked for people's opinion on whether closing local newspapers would hurt civic life; 426 of 1007 respondents said it would hurt civic life a lot. Complete parts a through d below. a. Find the proportion of the respondents who said that closing local papers would hurt civic life a lot. (Round to three decimal places as needed.) In a past presidential election, 32,330,202 people voted for Candidate A; 32,097,032 for Candidate B; and 153,080 for third-party candidates. a. What percentage of voters chose Candidate A? b. Would it be appropriate to find a confidence interval of voters choosing Candidate A? Why or why not? a. Find the percentage of voters who chose Candidate A. Each student in a class of GO was randomly assigned one line of a random number table. Each student then counted the odd-numbered digits in a 30-digit line. The even digits are 0, 2, 4, 6 and B. n. On average, in the list of 30 digits, how many odd-numbered digits would each student find? b. If each student found a 80%% confidence interval for the percentage of odd-numbered digits in the entire random number table, how many intervals (out of 60) would you expect not to capture the population percentage of 50%? A poll reported that only 832 out of a total of 2082 adults in a particular region said they had a "great deal of confidence" or "quite a lot of confidence" in the public school system. This was down 5 percentage points from the previous year. Assume the conditions for using the CLT are met. Complete parts (a) through (d) below. a. Find a 95%% confidence interval for the pro and interpret this interval. The 95% confidence interval for the proportion that express a great deal of confidence or tools is (D. (Round to three decimal places as needed.) A random sample of likely voters showed that 56% planned to support Measure X. The margin of error is 5 percentage points with a 99% confidence level Complete parts (a) through (c) below a. Use a carefully worded sentence to report the 99% confidence interval for the percentage of voters who plan to support Measure X. that the of likely voters who plan to support Measure X is between % and%% (Use ascending order.) A poll asked adults in a certain country whether immigration was a good thing or a bad thing for the country. Out of 1021 respondents, 545 said it was a good thing. a. What percentage of those taking the poll said immigration was a good thing? b. Check the conditions to determine whether you can apply the CLT to find a confidence interval. C. Find a 95% confidence interval for the proportion who believe immigration is a good thing. a. % of those taking the poll said immigration was a good thing. (Round to one decimal place as needed.) Each student in a class of 50 was rand m number table. Each student then and digits in a 40-digit line. The even digits are 0, 2, 4, 6 and 8. a. On average, in the list of 40 digits, how each student find? b. If each student found a 90% confidence interval for the percentage of odd-numbered digits in the entire random number table, how many intervals (out of 50) would you expect not to capture the population percentage of 50%%

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