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In an article in the Journal of Advertising , Weinberger and Spotts compare the use of humor in television ads in the United States and
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 140 use humor, while a random sample of 500 television ads in the United States reveals that 128 use humor.
Chrome File Edit View History Bookmarks Profiles Tab Window Help Question S X Course He X Course He x | C In An Artic x C In An Artic x C Solved: A X C A Consum X C C ezto.mheducation.com/ext/map/index.html?_con=con&external_browser=0&launchUrl=https%253A%252F%252Fnewconnect.m Youtube Canvas baylor email Login | Free State... ExponentHR - Log. DFPS - Child-Care.. DFPS PMET-PCS. A Intern Assignment Chapter 11 i Submitted You received partial credit in the previous attempt. 9 c) Set up the hypotheses needed to attempt to establish that the difference between the proportions of U.K. and U.S. ads using humor s more than .05 (five percentage points). Test these hypotheses by using a p-value and by setting a equal to .10, .05, .01, and .001. How much evidence is there that the difference between the proportions exceeds .05? (Round the proportion values to 3 decimal places. Round your z value to 2 decimal places and p-value to 4 decimal places.) 7.5/10 points awarded Z Scored 2.11 X p-value 0.0176 X Book Hint Reject HO at each value of a = .10 and a = .05; some x evidence. Print References (d) Calculate a 95 percent confidence interval for the difference between the proportion of U.K. ads using humor and the proportion of U.S. ads using humor. Interpret this interval. Can we be 95 percent confident that the proportion of U.K. ads using humor is greater than the proportion of U.S. ads using humor? (Round the proportion values to 3 decimal places. Round your answers to 4 decimal places.) 0. 1544 1 95% of Confidence Interval 0.0336 , Hill 99 4 P W MacBook Air DII FB 20 888 F5 F6 F7 F3 F 4 F1 % # 5 6 N 3(a) Set up the null and alternative hypotheses needed to determine whether the proportion of ads using humor in the United Kingdom differs from the proportion of ads using humor in the United States. HO: p1 - p2 0 versus Ha: p1 - p2 # 0 . (b) Test the hypotheses you set up in part a by using critical values and by setting a equal to .10, .05, .01, and .001. How much evidence is there that the proportions of U.K. and U.S. ads using humor are different? (Round the proportion values to 3 decimal places. Round your answer to 2 decimal places.) Z 3.06 Reject HO at each value of a; extremely strong evidence.(c) Set up the hypotheses needed to attempt to establish that the difference between the proportions of U.K. and U.S. ads using humor s more than .05 (five percentage points). Test these hypotheses by using a p-value and by setting a equal to .10, .05, .01, and .001. How much evidence is there that the difference between the proportions exceeds .05? (Round the proportion values to 3 decimal places. Round your z value to 2 decimal places and p-value to 4 decimal places.) Z 2.11 p-value 0.0176 Reject Ho at each value of a = .10 and a = .05; very strong evidence. (d) Calculate a 95 percent confidence interval for the difference between the proportion of U.K. ads using humor and the proportion of U.S. ads using humor. Interpret this interval. Can we be 95 percent confident that the proportion of U.K. ads using humor is greater than the proportion of U.S. ads using humor? (Round the proportion values to 3 decimal places. Round your answers to 4 decimal places.) 95% of Confidence Interval 0.0336 0.1544 ] Yes the entire interval is above zeroStep by Step Solution
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