In an asenkron transmission a character size is 6 bits. When 2100 characters are transmitted, if total overhead amount is 42 Kbit, which answer is correct? O a. Stop Bit = 1,5 Parity = "Even" Total Data Size = 19,00 Kbit O b. Stop Bit = 1,5 Parity = "No" Total Data Size = 18,70 Kbit O c. Stop Bit = 1 Parity = 'No' Total Data Size = 16,80 Kbit O d. Stop Bit = 2 Parity = "Even" Total Data Size = 25,00 Kbit O e Stop Bit = 2 Parity = "Even" Total Data Size = 18,00 Kbit