Question
In c++, Can Anyone make these code into user input code. Use have to input zipcode and barcode. #include #include #include //for exit() using namespace
In c++, Can Anyone make these code into user input code. Use have to input zipcode and barcode.
#include #include #include //for exit() using namespace std; class PostalCode{ public: PostalCode(int zip); //inputs zip code as an integer PostalCode(string bar); //inputs zip code as a string (0, 1) int getZipCode(); //returns the zip code as an integer string getBarCode(); //returns the zip code as a string private: int zipCode; string barCode;
bool checkBarCode(); //returns true if first and last digits of the bar code is 1 //and length of bar code is 27 bool checkTwoOnes(); //returns true if there is exactly two 1's in each group of 5 digits int calculateZipCode(); //returns the final zip value string getFiveDigitValues(); }; PostalCode::PostalCode(int zip) : zipCode(zip){} PostalCode::PostalCode(string bar) : barCode(bar){}
int PostalCode::getZipCode(){ if(checkBarCode()){ //if bar code is in right format if(checkTwoOnes()){ //if two ones in every five digits zipCode = calculateZipCode(); } else{ cout exit(1); } } else{ cout exit(1); } return zipCode; }
string PostalCode::getBarCode(){ barCode = getFiveDigitValues(); barCode = "1"+barCode+"1"; return barCode; } bool PostalCode::checkBarCode(){ bool result; if((barCode.length() == 27) && ((static_cast(barCode[0]) - 48) == 1) && ((static_cast(barCode[26]) - 48) == 1)){ result = true; } else{ result = false; } return result; } bool PostalCode::checkTwoOnes(){ bool fiveCases[5]; //stores true if each five digit group contains //two ones int arrCount = 0; int numberOnes; //number of number ones bool result = true; for(int i = 1; i=25;> numberOnes = 0; //resetting the value of numberOnes for next loop for(int j = i; j=i+4;> if((static_cast(barCode[j]) - 48) == 1){ numberOnes++; } } if(numberOnes == 2){ fiveCases[arrCount] = true; } else{ fiveCases[arrCount] = false; } arrCount++; } for(int i = 0; i5;> if(fiveCases[i] == false){ result = false; break; } } return result; } int PostalCode::calculateZipCode(){ int result = 0; int sumArr[5]; //stores sum of five five digit group of numbers int arrCounter = 0; int sum; int tempCounter; //to count first, second third, fourth, fifth value for(int i = 1; i=25;> sum = 0; //reseting the value of sum after each five digits tempCounter = 1; //reseting the value of tempCounter for(int j = i; j=i+4;> if(tempCounter == 1){ sum += (static_cast(barCode[j]) - 48)*7; tempCounter++; } else if(tempCounter == 2){ sum += (static_cast(barCode[j]) - 48)*4; tempCounter++; } else if(tempCounter == 3){ sum += (static_cast(barCode[j]) - 48)*2; tempCounter++; } else if(tempCounter == 4){ sum += (static_cast(barCode[j]) - 48)*1; tempCounter++; } else if(tempCounter == 5){ sum += (static_cast(barCode[j]) - 48)*0; tempCounter++; }
} if(sum == 11){ sum = 0; } sumArr[arrCounter] = sum; //storing the sum in array arrCounter++; } int multiplier = 10000; //now, converting the values in arr into an integer number for(int i = 0; i5;> result += sumArr[i] * multiplier; multiplier = multiplier/10; } return result; } string PostalCode::getFiveDigitValues(){ string result = ""; int divisor = 10000; int number = zipCode; int currentDigit; for(int i = 0; i5;> currentDigit = number/divisor; switch(currentDigit){ case 0: result += "11000"; break; case 1: result += "00011"; break; case 2: result += "00101"; break; case 3: result += "00110"; break; case 4: result += "01001"; break; case 5: result += "01010"; break; case 6: result += "01100"; break; case 7: result += "10001"; break; case 8: result += "10010"; break; case 9: result += "10100"; break; default: result += "00000"; cout } number = number % divisor; divisor = divisor/10; } return result; } int main(){ PostalCode pc("110100101000101011000010101"); cout cout //change here only PostalCode psl(99505); cout cout return 0; }
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