Question
In C write a function that computes the integer square root of an integer. long isqrt(long num); The integer square root of an integer is
In C write a function that computes the integer square root of an integer. long isqrt(long num); The integer square root of an integer is the largest integer whos square is less than or equal to the argument. The integer square root of 1 is 1. The integer square root of 30 is 5 because 5*5 <= 30 but 6*6 >30. The integer square root of 100 is 10 because 10*10 <= 100 but 11*11 >100. As above, make this a pure function contained in its own file called isqrt.c. This will be a tiny file. Assume that arguments are zero or positive. Create a separate testing program. Compile and run by: C:\Source\>gcc sqrtTester.c isqrt.c C:\Source\>.\a.exe Enter num: 3763 isqrt is 61 Write isqrt()as a loop that checks trial divisors starting at 2 and going up until trial*trial > N. Then return trial-1.
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