in Java build a grading app that needs to enter a. #1 Score (0 50 points), b. #2 Score (0 50 points), c. #3 Score (0 50 points), d. #4 Score (0 50 points), e. Assignment #1 Score (0 75 points), f. Assignment #2 Score (0 75 points), g. Assignment #3 Score (0 75 points), h. Assignment #4 Score (0 75 points). Let us arbitrarily select ten students and assignment scores like below: [35 43 22 37 64 60 51 47 48 44 46 43 47 38 40 29 25 20 19 29 66 69 68 68 39 33 35 27 38 44 71 58 41 40 37 35 40 38 37 68 49 47 38 47 63 52 61 50 43 43 45 41 67 68 50 49 35 30 19 39 46 59 58 69 40 43 45 47 68 64 61 62 43 41 39 38 52 58 57 58] After entering all the scores, the maximum scores one student can get is 500. Based on the criteria given below, print the grade for the instructor. FinalScore >= 450 : A, FinalScore> =400: B, FinalScore> =350: C, FinalScore>= 300: D, Else : F. However, since the instructor is very generous, he wants to give better grades to the students based on the statistics of the students Say, the distribution of the total points and the mean values of 10 students are 44.875 41.875 45.500 43.125 42.000 50.875 50.750 44.375 53.750 48.250 Then, the criterion of the grade A is A: >= Average of the students + (2 Standard Deviation of the students) B: >= Average of the students + (1 Standard Deviation of the students) (but less than A) C: >= Average of the students (but less than B) D: >= Average of the students (1 Standard Deviation of the students) (but less than C) F: < Average of the students (2 Standard Deviation of the students) 359 335 364 345 336 407 406 355 430 386 There is a catch for this assignment. The thing is that the mean and the standard deviation sometimes do not exactly cover the entire system. Say your mean is 50 and your standard deviation is only 2.5. Then, however you do, you cannot clearly divide between A and B, B and C because doubling only covers up to 5. So, C is between 55 and 45. There will be some gaps. What about too much standard deviation? Say, it is 10. Then, there will be some overlaps. So, the trick is depending on the standard deviation and t