In July of 2013, Australians were asked if they thought unemployment would increase, and 47% thought that it would increase. In November of 2013, they were asked again. At that time 760 out of 1800 said that they thought unemployment would increase. At the 2% level, is there enough evidence to show that the proportion of Australians in November 2013 who believe unemployment would increase is lower than the proportion who felt it would increase in July 2013? P: PARAMETER

What is the correct parameter symbol for this problem? ? X p X s N p n What is the wording of the parameter in the context of this problem? Select an answer All Australians in November 2013 that are believe unemployment would increase Whether or not a randomly selected Australian in November 2013 believes unemployment would increase All Australians in November 2013 A randomly selected Australian in November 2013 that believes unemployment would increase 1800 randomly selected Australians in November 2013 A randomly selected Australian in November 2013 The percentage of all Australians in November 2013 that believe unemployment would increase The percentage of 1800 randomly selected Australians in November 2013 that believe unemployment would increase H: HYPOTHESES

Fill in the correct null and alternative hypotheses:

H0:H0: ? N X s p p n X ? > < = HA:HA: ? p X p X s n N ? > = <

A: ASSUMPTIONS

Since Select an answer qualitative quantitative information was collected from each object, what conditions do we need to check?

Check all that apply.

• is unknown.
• np10np10
• n30n30 or normal population.
• is known.
• N20nN20n
• n(1p)10n(1-p)10

Check those assumptions: 1. npnp = which is ? = 2. n(1p)n(1-p) = which is ? = 3. NN = which is ? =

If no N is given in the problem, use 1000000 N: NAME THE PROCEDURE

The conditions are met to use a Select an answer 1-Proportion Z-Test T-Test . T: TEST STATISTIC

The symbol and value of the random variable on this problem are as follows:

Leave this answer as a fraction.

? X N p p X n s =

The formula set up of the test statistic is as follows.:

(Leave any values that were given as fractions as fractions)

z=ppp(1p)n=z=p-pp(1-p)n= ( - )/((/(( (1(1- ))// ))

Final answer for the test statistic from technology.

Round to 2 decimal places:

z =

O: OBTAIN THE P-VALUE

Report to 4 decimal places.

It is possible when rounded that a p-value is 0.0000 P-value = M: MAKE A DECISION

Since the p-value ? > = , we Select an answer reject H reject H fail to reject H fail to reject H accept H .

S: STATE A CONCLUSION

There Select an answer is is not significant evidence to conclude Select an answer The percentage of 1800 randomly selected Australians in November 2013 that believe unemployment would increase All Australians in November 2013 that are believe unemployment would increase All Australians in November 2013 Whether or not a Australian in November 2013 believes unemployment would increase The percentage of all Australians in November 2013 that believe unemployment would increase A randomly selected Australian in November 2013 that believes unemployment would increase 1800 randomly selected Australians in November 2013 A randomly selected Australian in November 2013 Select an answer is less than differs from is equal to is more than