In one mole of a gas at a temperature of 650 K (kT = 8.97 10-21 J = 0.0560 eV), calculate the number of molecules with energies between 0.0105 eV and 0.0135 eV. (b) In this gas, calculate the fraction of the molecules with energies in the range of 2.5% of the most probable energy (KT). N(E) (x 10-25) N(E) (x 10-25) 0.50 0.40 0.30- 0.20 0.10 0.00 + 0.008 0.010 0.012 0.014 0.016 0.50 0.40 0.30- 0.20- 0.10 0.00 Energy (eV) (a) 0.026 0.027 0.028 0.029 0.030 Energy (eV) (b)