In Problems 15 through 18, given information: Ms. Gilmore opened her saving account and deposited $1800 on 11/11/2012. On 11/11/2013, her balance was $1900, and she withdrew $100, giving a balance of $1800. On 11/11/2015, her balance was 2000, and she deposited $400, giving a balance of $2400. On 11/11/2016, she had a balance B = $2800. 15. To find the Dollar-Weighted Yield Rate i = low, we have to solve an equation of 1800(1 +1) - 100(1 + 1) + 400(1+1) = 2800 at t = 4. Which of the following equations at t - 0 is the same as this equation at t -4. a). 1800v* - 100v2 + 400 = 2800 b). 1800v2 - 100v2 + 400v - 28000 c). 1800 - 100V + 400 v2 = 2800 d. 1800 - 1000 + 400v* - 2800v4 16. Find the Dollar-Weighted Yield Ratei - Lby solving an equation of 1800(1+1)* - 100(1 + 0 + 400(1+ - 2800 by Tl-Salculator. (Hint: Set Window: Xmin = 0. Xmax = 0.10. Ymin=0. Ymax = 3000) a). 6.5% b). 7.5% c). 8.5% d). 9.5% 17. To find the Time-Weighted Yield Rate i = lrw, we need to find (1 + 1)(1+ /2) (1 +13) a). (19/18)(20/19) (28/20) b). (19/18)(20/18)(28/24) c). (18/19) (19/20)(20/28) d). (28/18)(20/19) (24/18) 18. Find the Time-Weighted Yield Rate i = irw= a). 9.055% b). 8.155% c).7.255% d). 6.355%