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In the below formula: S = v0 t a t^2 Distance is equal to the initial velocity multiplied by time plus one half acceleration times
In the below formula: S = v0 t a t^2 Distance is equal to the initial velocity multiplied by time plus one half acceleration times time squared. What is true about the acceleration in order for the formula to be accurate? Group of answer choices It has to be zero Neither of the other answers is correct It has to be constant
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Quantum Physics For Beginners From Wave Theory To Quantum Computing Understanding How Everything Works By A Simplified Explanation Of Quantum Physics And Mechanics Principles
Authors: Carl J. Pratt
1st Edition
B08YQJD281, 979-8718003864
