In the following network, the activation function in all the units is the identity: f(z)=z. Someone correctly claims it would be just as effective to use this second network below instead. Supply expressions for v0', v1' and v2' for the second network, in terms of the first one's weights w01, w11, w12, w02, w21, w22, v0, v1, and v2, such that the second network is equivalent to the first one. . Enter expressions in terms of w01, w11, w12, w02, w21, w22, v0, v1, and v2. . VO'=