In the game of Yahtzee, a full house is when a player rolls three of one number and two of another number across three rolls of the dice. ie, three 4s and two 3s, or three 6s and two 1s. etc.

Suppose I am playing Yahtzee, and through two of my three rolls, I have accumulated two 4s and one 3 showing with one roll to go.That means I need my last two dice to come up as a 4 and a 3, in some fashion, so that I end up with three 4s and two 3s. What is the probability, when I roll the last two dice simultaneously, that I will achieve a full house on my last roll?