In the next couple of questions, we'll continue to use the limit form of the comparison test to determine whether or not some improper integrals converge or diverge. Warning: Attempt to explicitly evaluate the corresponding indefinite integrals in terms of elementary functions at your own peril! In particular, consider the improper integral 1 = / f(z) da. We wish to find a simple positive-valued function g for which a) lim f(x) exists and is positive, and T-+00 g() R b) g(x) da is easy to evaluate. If this is a valid choice of function, then you can give the following array of data: f(I) R A = g(x), lim g(x) dx, lim 2-+00 g(x) R-+0o ha(z) da Note: Remember to write your answers using Matlab syntax. If the improper integral diverges, write the answer as Inf For example, the array [ In VI, 1, 2RX, co] would be written as [log (sqrt (x) ) , 1, 2*R^2, Inf] In this question, do NOT omit commas between entries! Suppose f is the function given by the rule 1 f(I) = 12 + Inc Then we may choose a function g to get the data A = Hence, the improper integral I converges