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In this Investigation you will explore an application of exponential functions. The goal of this assignment is to apply the skills you learned in the
In this Investigation you will explore an application of exponential functions. The goal of this assignment is to apply the skills you learned in the last unit and see how exponential functions are applicable to your lives. Please see the attached file for the project information and questions. WakeUpandSmellTheCoffee.pdf Here is what I need you to submit. Type a report that includes the following: 1. An introduction that gives an overview of this Investigation. 2. Answers to all the questions for You Try It 1 - 7. . Include any tables that you were asked to make. Include all required graphs in the document. Make graphs using Desmos (www.desmos.com). 3. Discussion: Post your You Try It #4 table and graph in the Investigation 2 Discussion forum. Reply to two other students. In your replies you can: Ask students clarification questions . Share methods and strategies for making the graph and help each other with the process . Compare your caffeine consumption with that of your group members 4. Write a conclusion paragraph reflecting on the work you did, the math you used and your opinion of the investigation and the results that you got. Submit one file in pdf format by clicking Submit and uploading your file. Here is a sample of a table used to track caffeine consumption over a 24 hour period and the functions and graph that models the caffeine consumption: Caffeine Consumption.pdfCaffeine Consumption Time of Caffeine Intake 6:30 am 9:00 am 3:00 pm 5:00pm 7:00pm 9:30pm Amount of caffeine in body before consuming 0 31.77mg 33.29mg 59.71mg 68.66mg 80.24mg the caffeine Amount of caffeine in this drink or food 45mg 45mg 45.6mg 31mg 45mg 45mg Function that describes amount of caffeine in your body from now f(t) =45(.87) f(t) =76.77(.87)t 2.5 f[t) =78.89(.87)t as f[t) =90.71(.87)-105 f(t) =113.66(.87)1 12.5 f(t) =125.24(.87)t-15 until your next caffeine Oct 15 consumption X 45(.87)" (0
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