Question
In this lab, you will be working with the following tables in SQL Server. To create and populate these tables in SQL Server, run the
In this lab, you will be working with the following tables in SQL Server. To create and populate these tables in SQL Server, run the queries that are listed below these tables.
CUSTOMER
CID | CName | Age | Resid_City | BirthPlace |
1 | BLACK | 40 | ERIE | TAMPA |
2 | GREEN | 25 | CARY | ERIE |
3 | JONES | 30 | HEMET | TAMPA |
4 | MARTIN | 35 | HEMET | TAMPA |
5 | SIMON | 22 | ERIE | ERIE |
6 | VERNON | 60 | CARY | CARY |
7 | WILSON | 25 | DENVER | AUSTIN |
In the CUSTOMER table, CName is the primary key.
RENTALS
Rtn | CID | Make | Date_Out | Pickup | Date_returned | Return_city |
1 | 1 | FORD | 10-Oct-2010 | CARY | 12-Oct-2010 | CARY |
2 | 1 | GM | 01-Nov-2009 | TAMPA | 05-Nov-2009 | CARY |
3 | 1 | FORD | 01-Jan-2009 | ERIE | 10-Jan-2009 | ERIE |
4 | 2 | NISSAN | 07-Nov-2010 | TAMPA |
|
|
5 | 3 | FORD | 01-Oct-2010 | CARY | 31-Oct-2010 | ERIE |
6 | 3 | GM | 01-Aug-2009 | ERIE | 05-Aug-2009 | ERIE |
7 | 4 | FORD | 01-Aug-2010 | CARY | 12-Aug-2010 | ERIE |
8 | 5 | GM | 01-Sep-2010 | ERIE |
|
|
In the table RENTALS, Rtn is the primary key and represents the rental number. CID is a foreign key in the RENTALS table and refers to the CID in CUSTOMER; Pickup is the city where the car was picked up; and Date_Out is the date in which the car was rented out. Return_city is the city where the car was returned. Date_returned is the date in which the vehicle was returned. If the car has not yet been returned, Date_returned and Return_city are null.
RENTCOST
MAKE | COST |
FORD | 30 |
GM | 40 |
NISSAN | 30 |
TOYOTA | 20 |
VOLVO | 50 |
The RENTCOST table stores the rates per day of each vehicle. The primary key of this table is MAKE, and it is a foreign key in the RENTALS table.
create database AutoRentals
go
use AutoRentals
go
create table Customer
(CID integer,
CName varchar(20),
Age integer,
Resid_City varchar(20),
BirthPlace varchar(20),
Constraint PK_Customer Primary Key (CID))
insert Customer
select 1, 'Black', 40, 'Erie', 'Tampa'
insert Customer
select 2, 'Green', 25, 'Cary', 'Erie'
insert Customer
select 3, 'Jones', 30, 'Hemet', 'Tampa'
insert Customer
select 4, 'Martin', 35, 'Hemet', 'Tampa'
insert Customer
select 5, 'Simon', 22, 'Erie', 'Erie'
insert Customer
select 6, 'Vernon', 60, 'Cary', 'Cary'
insert Customer
select 7, 'Wilson', 25, 'Denver', 'Austin'
create table Rentcost
(Make varchar(20),
Cost float,
constraint PK_Rentcost Primary Key (Make))
insert Rentcost
select 'Ford', 30
insert Rentcost
select 'GM', 40
insert Rentcost
select 'Nissan', 30
insert Rentcost
select 'Toyota', 20
insert Rentcost
select 'Volvo', 50
Create table Rentals
(Rtn integer,
CID integer,
Make varchar(20),
Date_Out smalldatetime,
Pickup varchar(20),
Date_returned smalldatetime,
Return_city varchar(20),
Constraint PK_Rentals Primary Key (Rtn),
Constraint FK_CustomerRentals Foreign Key (CID) References Customer,
Constraint FK_RentCostRentals Foreign Key (Make) References Rentcost)
insert Rentals
select 1, 1, 'Ford', '10/10/2010', 'Cary', '10/12/2010', 'Cary'
insert Rentals
select 2, 1, 'GM', '11/1/2009', 'Tampa', '11/5/2009', 'Cary'
insert Rentals
select 3, 1, 'Ford', '1/1/2009', 'Erie', '1/10/2009', 'Erie'
insert Rentals
select 4, 2, 'Nissan', '11/7/2010', 'Tampa', null, null
insert Rentals
select 5, 3, 'Ford', '10/1/2010', 'Cary', '10/31/2010', 'Erie'
insert Rentals
select 6, 3, 'GM', '8/1/2009', 'Erie', '8/5/2009', 'Erie'
insert Rentals
select 7, 4, 'Ford', '8/1/2010', 'Cary', '8/12/2010', 'Erie'
insert Rentals
select 8, 5, 'GM', '9/1/2010', 'Erie', null, null
25. execute a single query that will display all of the information in the Customer, Rentals, and Rentcost tables in a single resultset. Be sure to display each field only once in your output. Order your results in ascending order by Customer.CID and Rentcost.Make .
You should have 12 rows and 12 columns in your result.
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