#include #include #include using namespace std;

int main() { char v[20]; int sign, n, i; float result, nr, aux, c; while (1) { cout << "insert the expression:" << endl; scanf("%s", v); n = strlen(v); result = 0, nr = 0, aux = 0, c = 0; sign = 1, n, i = 0; while (i { while (v[i] >= '0'&&v[i] <= '9')//builds the number { nr = nr * 10 + (v[i] - '0'); i++; } switch (v[i])//identifies the operations { case '+': {

if (!(v[i - 1] == '') && !(v[i - 1] == '/'))//if a-b or a/-b occurs it does nothing { if (c == 1)// * was found before: 2*2+1 { result += aux*nr*sign;// updates the end result aux = 0;//aux is reseted } else if (c == 2)// / was found before: 2/2+1 { result += aux / nr*sign; aux = 0; } else { result += nr*sign; } nr = 0; c = 0; }

sign = 1;

break; } case '-': { if (!(v[i - 1] == '*') && !(v[i - 1] == '/')) { if (c == 1) { result += aux*nr*sign; aux = 0; } else if (c == 2) { result += aux / nr*sign; aux = 0; } else { result += nr*sign; } c = 0; nr = 0; } sign = -1; break; } case '*': { if (!aux) { aux = nr*sign; // aux hold the result from * and / operations } else if (c == 2) { aux /= nr*sign; } else { aux *= nr*sign; } c = 1; nr = 0; sign = 1; break; } case '/': { if (!aux) { aux = nr * sign; } else if (c == 1) { aux *= nr*sign; } else { aux /= nr*sign; } c = 2; nr = 0; sign = 1; break; } default:; } if (i >= (n - 1))// updates the result because there is no + or - at the end of the string. { if (c == 1) { result += aux*nr*sign; } else if (c == 2) { result += aux / nr*sign; } else { result += nr*sign; } } i++; } cout << "=" << result << endl; system("pause"); system("cls");

} }

Hi can anyone of you convert this program in C++ to C program. Will give good rate if really helping. Thank you