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#include #include using namespace std; int func1(int n) { // the given function 1 return n*n + n +41; } int func2(int n) { //

#include #include

using namespace std;

int func1(int n) { // the given function 1 return n*n + n +41; } int func2(int n) { // the given function 2 return n*n - 79*n + 1601; } int func3(int n, int a, int b) { // the given function 3 return n*n + a*n + b; }

int isPrime(int y){ //to check whether the number is prime or not if(y<0) { return 0; } for(int i=2; i<=sqrt(y); i++){ if(y%i==0) return 0; } return 1; }

void printPrimeswith40(){ // to print prime till n 40 for(int i=0; i<40; i++){ int j = func1(i); if(isPrime(j)) { cout<

void printPrimeswith80(){ // to print prime till n 80 for(int i=0; i<80; i++){ int k = func2(i); if(isPrime(k)) { cout<

void printMaxAB(){ // to print max a and b from given n range int a, b, c, j, n, maxa=0, maxb=0, maxn=0;

for(a=-999; a<1000; a++){

for(b=-1000; b<=1000; b++){

n=0, c=0; do{ j = func3(n, a, b); c++;n++; }while(isPrime(j));

if(n>maxn){ maxa = a; maxb = b; maxn = n; } } } cout<<"a= "<

cout<<" 80 prime numbers: "<

cout<

return 0;

}

For the above program:

1. The isPrime() function. What is the time complexity of this function?

2. Tune the program to limit variable b to prime numbers only, since when n is 0, all we have is 0*0 + a * 0 + b = b. Thus b must be a prime number.

3. Tune the code to print all consecutive prime numbers from the longest sequence.

4. And also present the implementation of Array List.

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