For the beam below: (a) Find the reactions for the structure below using the Force Method. (b) Find rotation of the beam at point A. Assume El is constant along the entire length of the beam. A A 1 Kips/ft 10 ft Ain B + 5 ft AM C 0, -4/2- Beam 1 4 7 10 8 = 8== 0 =- SIMPLY SUPPORTED BEAMS Slope Deflection 16 13 0 =- 0 = + |0=+ Pb(L-b) 6LEI Pa(L-a) 6LEI q= 8=-0=- 8=+ PL 16EI ML 3EI ML 6EI wa 24LEI 0=+ wa 24LEI w 24EI -(2L-a) (21-a) 7w.1 360 EI w.L 45EI 2 5 8 11 14 V= 17 V=-- PI 48EI Pab 3LEI at x = a wa' 24LEI ML 93 EI *x-Z(1-4) at x= 5wL 384EI (41-7aL+3a) at x=a Vmax=-0.00652- at x=0.5193Z 3 6 19 V=- 12 V= |v=- 15 18 Elastic Curve Px 48EI y=- -(31-4x) Pbx 6LEI wa 24LEI Mx 6LEI -(1-b-x) WX 24EI for 0x4/2 for 0x a (213Lx+x) WX 24LEI -4a'L+a) for 0xa (L - 2Lx + x) (Lx-4aLx +2ax +4aL Wox 360LEI =(2x-6Lx + ax+4Lx-aL) for asxsL (71-10Lx + 3x)