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instructor ( ID , name , dept_name , salary ) teaches ( ID , course id , sec id , semester , year ) 3.

instructor(ID, name, dept_name, salary)

teaches(ID, course id, sec id, semester, year)

3. Write an equivalent relational algebra expression for the following using natural join and the above given schemas.

_name (s_{instructor.ID} _=teaches.ID (s_{dept_name} ₌_Physics (instructor teaches)))

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