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int numbers [37] ; int iptr = &numbers [0] for each expression below that uses one notation (pointer or array index), give the equivalent expression

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int numbers [37] ; int iptr = \&numbers [0] for each expression below that uses one notation (pointer or array index), give the equivalent expression of the other type. The first one is done for you. a. numbers [0] is equivalent to iptr b. ( iptr+2) is equivalent to c. numbers [n] is equivalent to d. (iptr+(iptr+1)) is equivalent to

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