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Integer. Perform the following calculations. a ) ( 0 1 1 0 1 1 1 1 ) 2 C + ( 0 0 1 1

Integer. Perform the following calculations.
a)(01101111)2C +(00110110)2C =(10100101)2C
Is there an overflow? Please explain.
No because the sum is within the range for 8-bit 2 complement
numbers
b)(01001001)2(00101111)2=(10011010)2, assuming 8-bit
system and unsigned binary number

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