Integrate f (1:, y, z) = LUZV4 z2 312 over the path 0, which consists of two curves, Cl and 02, from (1, 0, 0) to {-1, 0, 0), then to (-1, 4, 0). See the diagram below. Curve Cl is only half of the circle 3:2 + Z2 = 1. Curve 02 is a straight-line segment. The parametric equation for 01 is '71 (t) = cos #2 + 51113523, 0 g t g 71' (a) Write the parametric equation for 02 . (b) Calculate the line integral: L f (3:, y, 2) d5