integration.

Match each double integral $in$ polar with the graph $of$ the region $of$

${\displaystyle \underset{3\frac{}{4}}{\overset{3\frac{}{2}}{}}}{\displaystyle \underset{0}{\overset{4}{}}}f(r,)rdrd$

${\displaystyle \underset{3\frac{}{2}}{\overset{2}{}}}{\displaystyle \underset{0}{\overset{5}{}}}f(r,)rdrd$

${\displaystyle \underset{0}{\overset{2}{}}}{\displaystyle \underset{0}{\overset{4}{}}}f(r,)rdrd$

${\displaystyle \underset{0}{\overset{4}{}}}{\displaystyle \underset{-\frac{}{2}}{\overset{3\frac{}{4}}{}}}f(r,)rddr$

${\displaystyle \underset{-\frac{}{4}}{\overset{3\frac{}{4}}{}}}{\displaystyle \underset{4}{\overset{5}{}}}f(r,)rdrd$

${\displaystyle \underset{0}{\overset{4}{}}}{\displaystyle \underset{0}{\overset{3\frac{}{4}}{}}}f(r,)rddr$

${\displaystyle \underset{0}{\overset{2}{}}}{\displaystyle \underset{4}{\overset{5}{}}}f(r,)rdrd$

${\displaystyle \underset{4}{\overset{5}{}}}{\displaystyle \underset{3\frac{}{4}}{\overset{7\frac{}{4}}{}}}f(r,)rddr$

$A$

$D$

$B$

$C$

$E$