Question
Interarrival Time Distribution: Exponential of mean = 3.5 min Service Duration Distribution: Exponential of mean = 5 min Using the Midsquare Method X0 = 8798,
Interarrival Time Distribution: Exponential of mean = 3.5 min
Service Duration Distribution: Exponential of mean = 5 min
Using the Midsquare Method X0 = 8798, generate random numbers x1 to x30 to derive the interarrival times of the customers and the using the mixed(linear) congruential method: Use X0 = 8798, a=41, c=17, m=10,000 random numbers x1to x30 to derive the service duration of the customers
Make a table with the headings:
Customer Number, Random Number (whole number) for Inter-arrival time, RN(decimal) for Inter-arrival time, Inter-arrival time, Arrival time, Random Number (whole number) for Service Duration, Random Number (decimal) for Service Duration, Service Duration, Time Service Begins, Time Service Ends, Time Customer Waits in Queue, Idle Time of Server.
At the bottom of the table, indicate:
Total Service Duration, Total Time Customer Waits in Queue, and Total idle Time of Server. Compute the average waiting time of each customer and average service time of server.
Compute the table for 30 customers. Round your answers into 2 decimal numbers.
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Customer NumberRandom Number whole number for Interarrival timeRNdecimal for Interarrival timeInterarrival timeArrival timeRandom Number whole number for Service DurationRandom Number decimal for Serv...Get Instant Access to Expert-Tailored Solutions
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