Question
intergrate dW=KV+Ka^2sin^2(bt)dt+Ka^3sin^3(bt)dt so that it is equal to W=1/2KV^2T+1/4K^2fV^2T+2/3K^2f^2V^3T For refernce it is equation 4 and 5 on this website https://www.frontiersin.org/articles/10.3389/fphys.2021.772295/full#F1
intergrate dW=KV+Ka^2sin^2(bt)dt+Ka^3sin^3(bt)dt so that it is equal to W=1/2KV^2T+1/4K^2fV^2T+2/3K^2f^2V^3T
For refernce it is equation 4 and 5 on this website https://www.frontiersin.org/articles/10.3389/fphys.2021.772295/full#F1
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Infrared Technology Fundamentals
Authors: Monroe Schlessinger
2nd Edition
1351438344, 9781351438346
