IQ scores are normally distributed with a mean of 100 and standard deviation of 15 (= 100,= 15)

A. The proportion (probability) of the distribution with scores of 105 or more is _____

B. The proportion (probability) of the distribution with scores of 80 or less is ______

C. The proportion (probability) of the distribution with scores between the mean and 115 is ______

Suppose the average age of first marriage (normally distributed) in the USA for women is 27 years with a standard deviation of 1.2 years (= 27,= 1.2). What age (X value) would be considered in the top 10% (last 10% to get married)?

If you could please help me understand better thank you!