Iron reacts with $20\%$ hydrochloric acid and arise iron$($II$)$ chloride and hydrogen. Balance this chemical equation. For the reaction was used $37\mathrm{.}3g$ of iron $)=(55\mathrm{.}85.$

Calculate:

Volume of $20\%$ hydrochloric acid, needed for the reaction. $M_r(HCl)=36\mathrm{.}46$; density of the $20\%$ solution is $1\mathrm{.}098g*c{m}^{-3}$

Result $($two decimal places$)$: $mL$ of $20\%HCl$

Mass of iron$($II$)$ chloride, which can be obtained by this reaction. $M_r(ZnC{l}_2)=126\mathrm{.}75$

Result $($two decimal places$)$: $g$ of $ZnC{l}_2$

Volume of the hydrogen $($at the standard conditions$),$ which can be obtained by this reaction.

Result $($two decimal places$)$: L of $H_2$