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Is 2^n - 1000n -100 = worst case (n^2)? Express 0.01(n^2) + 10n + 1000(nlogn) + 2 in terms of big O.

Is 2^n - 1000n -100 = worst case (n^2)?

Express 0.01(n^2) + 10n + 1000(nlogn) + 2 in terms of big O.

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