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is the length of the pathway? y=((y)/(x)-(I^(2))/(x))x+1-1 The length of a tarpaulin is 3ft more than thrice its width and its area is 126ft^(2). What

is the length of the pathway? y=((y)/(x)-(I^(2))/(x))x+1-1 The length of a tarpaulin is 3ft more than thrice its width and its area is 126ft^(2). What of the tarpaulin? 1 answer

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