Is this correct? In part 1(not in the screenshot) it took me 20 rolls until I first rolled a one, so I am not sure if this part is correct(specifically the first part of the image).

X = # of rolls until a 1 is first rolled on a six sided die Explanation P(X = 1) = (1/6) P(rolling 1) The probability of rolling a 1 is 1/6 because a six sided die has 6 possible outcomes. Probability of not rolling a 1 is 5/6 because P(X = 2) = (5/6)*(1/6) P(rolling not-1)*P(rolling 1) P(X = 3) = (5/6)^2*(1/6) P(rolling not-1) 2*P(rolling 1) P(X = n) = (5/6)(n-1)*(1/6) P(rolling not-1)(n-1)*P(rolling 1) Look for a pattern here and explain The higher the value for n, the higher exponential value. As the value increased, (P(X=2),P(X=3), etc), so did the exponent. 10 your thinking- 11 12 13 i = 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 P(X