is this right To determine the minimum sample size necessary for a 95% confidence interval with a margin of error of 0.04, we use the formula for sample size for proportions: = 2 ( 1 ) 2 n= E 2 Z 2 p(1p) where: Z is the z-score corresponding to the desired confidence level (1.96 for 95% confidence), p is the estimated proportion (0.39), E is the margin of error (0.04). Let's calculate it: = ( 1.96 ) 2 0.39 ( 1 0.39 ) ( 0.04 ) 2 n= (0.04) 2 (1.96) 2 0.39(10.39) = 3.8416 0.39 0.61 0.0016 n= 0.0016 3.84160.390.61 = 0.9112 0.0016 n= 0.0016 0.9112 569.5 n569.5 Since you cannot have a fraction of a person, round up to the nearest whole number: = 570 n=570 Given the options, the closest is: 571In 2018, the percentage of Americans who skip a recommended medical test or treatment due to the cost was 39%. A similar study will be conducted this year to update this data. Determine the minimum sample size necessary to construct a 95% confidence interval with a margin of error of 0.04. 0.1 12 292 571 572 601 None of these answers are correct