It is believed that 11% of all Americans are left-handed. In a random sample of 200 students from a particular college with 20105 students, 20 were left-handed. Find a 94% confidence interval for the percentage of all students at this particular college who are left-handed.

Do is unknown. On(1 - p) 2 10 On > 30 or normal population. Check those assumptions: 1. np= 20 which is EV 10 2. n(1 - p)= 180 which is Evo 10 3. N= 20105 which is 2 4000 If no N is given in the problem, use 1000000 N: Name the procedure The conditions are met to use a 1-Proportion Z-Interval 1: Interval and point estimate The symbol and value of the point estimate on this problem are as follows: pv vo = Leave answer as a fraction. The interval estimate for p v . is Round endpoints to 3 decimal places. C: Conclusion We are % confident that The percentage of all students from this campus that are left-handed vo is between % and % Question Help: [Video Message instructor Submit Question Jump to