' It takes a golfer a total of three strokes to put the ball In the hole. The displacements of the three strokes are as follows: d1 = 4'10 m the north, d2 = 1.90 m northeast, and d3 = 1'00 m at 9 = 35.0 west of south, as shown In the gure. If the golfer had made the hole In a single shot, what would be the displacement of the ball? (Assume the positive y and x-axes are In the north and east directions, respectively. Give the magnitude of your answer In meters and the direction In degrees north of east.) N :12 I\": we. /i 5 o . d1 magnitude 0.9315 X Let +X be east, and +y be north. erte each of the displacements In unit-vector notation. Note that "northeast" means 45 north of east. Use the figure to help you determine the signs of the components, and sum the displacement vectors to find the , total displacement. Then use the Pythagorean theorem to nd the magnitude. m d I rectlon 34.2599 x . Use the components of the total displacement vector and the Inverse tangent function to calculate the angle. north of east di = 4. Im dz : 1.9 m Kys resutant ( dr ) do = /m / 40 35 or Component method? Ko X y di + 4. ) dr: 10 769 92 + 0. 82 4 42 d2 19 cos 48 1.9 sinks dr = 09315m d3 - 1 sin 35 -1 cos35 0.82 44 Sx= 0.7699m Zy = 0. 524ym D = tan ! 0.7699 D = 34. 28990