It takes? years and? days for an amount of money, invested at 6% p.a simple interest, to increase by 40%. Simple interest formula: F, = P (1 + i Pv increases by 40% F = P (1+40%) F = 1, 4P P (1 + in) = 1,4Pv 1 +0,06m = 1,4 Solve for n=6,666 years. NOTE - that n n = 6yrs + 0,666...yrs 6yrs +0, 666. Count the decimal as a whole day. It takes 6 years and 244 days. Answer the following = It takes type your answer... type your answer... days for an amount of money invested at 6% p.a simple interest, to double. ^ years and Next

It takes? years and? days for an amount of money, invested at 6% p.a simple interest, to increase by 40%. Simple interest formula: Fv=Pv(1+i Pv increases by 40\% Fv=Pv(1+40%)Fv=1,4PvPv(1+in)=1,4Pv1+0,06n=1,4 Solve for n=6,666 years. NOTE - that n n=6yrs+0,666yrs=6yrs+0,666. Count the decimal as a whole day. It takes 6 years and 244 days. Answer the following It takes years and days for an amount of money invested at 6% p.a simple interest, to double. It takes? years and? days for an amount of money, invested at 6% p.a simple interest, to increase by 40%. Simple interest formula: Fv=Pv(1+i Pv increases by 40\% Fv=Pv(1+40%)Fv=1,4PvPv(1+in)=1,4Pv1+0,06n=1,4 Solve for n=6,666 years. NOTE - that n n=6yrs+0,666yrs=6yrs+0,666. Count the decimal as a whole day. It takes 6 years and 244 days. It takes years and days for an amount of money invested at 6% p.a simple interest, to double