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It turns out that using the div operator to compute the modulo operation is slow! We can use a math trick to optimize the modulo
It turns out that using the div operator to compute the modulo operation is slow!
We can use a math trick to optimize the modulo operator Compilers use this trick a lot.
If we have x y and y is a power of such as n the result will be the lower n bits of x
Therefore, we can use the lower register byte access to efficiently implement modulo!
Using only the following instructions:
mov
Please compute the following:
rax rdi
rbx rsi
We will now set the following in preparation for your code:
rdi xe
rsi xeaea
Please give me your assembly in bytes up to x bytes:
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