it's just multiple choice IT'S 17 Q PLEASE ANSWER ALL OF IT

The hexadecimal number of the decimal num ber 105.25 is (A) 69.4 (C) 96.4 0 69.04 2.[ ] What encoding is used for real numbers in modern computers? (A) Fixed-point integer Fixed-point decimals Floating point numbers (D) ASCII 3.[ ] What encoding is used for signed numbers in modern computers Original code (B) 1's complement 2's Complement BCD code 4. How many bits is the width of a single- precision floating-point number? @ 16 32 (D) Changing 5. [ ] How many bits is the width of a double- precision floating-point number? 64 Changing 6.[ ] which is the binary number 1001.101 expressed as a normalized floating- point number A) 1.001101 x2 0.1001101 x 24 10.01101 x 2 0 100.1101 x 2 The bit width and deviation of the exponential field of a single-precision floating- point number are, respectively. @ 8: 127 7; 127 7; 128 D 8; 128 8.[ ] The bit width and deviation of the exponential field of a double-precision floating- point number are, respectively. (A) 11; 1023 13; 1024 13; 1023 (D) 11; 1024 which is the hexadecimal value of -9.625 represented in single-precision floating- point number (A) Oxc21a0000 (B) 0x81120000 0x821a0000 D) Oxc1120000 10.[ It is known that a computer system stores dat a in memory in small endianness. If halfword data 0x12ab is stored in the memory at addre ss Ox1000, the data stored in the storage unit at address Ox1001 is @ 0x12 Oxab Ox2a 11.[it ] single-precision floating- point number representation of 1.5 is (A) 0x3fc00000 (B) Oxbfc00000 ( C 0x4fc00000 (D) Oxbbfc0000 12.[! ] It is known that the storage data of a 32- bit computer system uses little- endian, and the storage unit starting from ad dress Ox2000 stores the data below. what is the corresponding decimal value of 32 bits integer at address Ox2000? Address 0x2000 Ox2001 0x2002 0x2003 Value 2 3 6 0 (A) 556 23 393986 13.[ 3] The two unsigned numbers are subtracted, th e Subtrahend is less than the subtractor, ther e is a borrow, the result is negative, and ther esult obtained at this time is (A) The original code B 1's Complement 2's Complement Absolute value 14.[ 4 ] When two signed numbers calculations result in overflow, it indicates that the result is Original code 1's Complement 2's Complement 15. Floating point arithmetic process produces ov erflow, which means When the result is normalized, the p ositive index value exceeds the maxi mum value that the index may repre sent. When the results are normalized, th e negative index value exceeds the minimum value that the index mayr epresent When the result is normalized, the m antissa exceeds the maximum value that the mantissa can represent When the result is normalized, the m antissa exceeds the minimum value that the mantissa can represent 16.[3 ] Among the data represented by the two's complement below, whose true value is - 8 [A] 0xF8 B ] 0xFFF8 OxFFFFFFF8 D0x88 17.3 Among the data represented by the two's complement below, whose true value is -128 A 0x80 B 0xFF80 (COXFFFFFF80 D 0x88